I have a string which needs a decimal place inserted to give a precision of 2.
3000 => 30.00
300 => 3.00
30 => .30
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Given a string input, convert to integer, divide by 100.0 and use String.Format() to make it display two decimal places.
String.Format("{0,0:N2}", Int32.Parse(input) / 100.0)Smarter and without converting back and forth - pad the string with zeros to at least two characters and then insert a point two characters from the right.
String paddedInput = input.PadLeft(2, '0') padedInput.Insert(paddedInput.Length - 2, ".")Pad to a length of three to get a leading zero. Pad to precision + 1 in the extension metheod to get a leading zero.
And as an extension method, just for kicks.
public static class StringExtension { public static String InsertDecimal(this String @this, Int32 precision) { String padded = @this.PadLeft(precision, '0'); return padded.Insert(padded.Length - precision, "."); } } // Usage "3000".InsertDecimal(2);Note: PadLeft() is correct.
PadLeft() '3' => '03' => '.03' PadRight() '3' => '30' => '.30'Samuel : He said the input is a string, not an integer.Murtaza RC : works like a charm ! thanks a lotMurtaza RC : well I can convert it to an int :)Samuel : Then you really should say that.Murtaza RC : There - you have your answer ...convert the string to int :)Daniel Brückner : Parsing if not required and converting back is not smart ... ^^ -
Use tryParse to avoid exceptions.
int val; if (int.Parse(input, out val)) { String.Format("{0,0:N2}", val / 100.0); }Samuel : You don't have to cast to double if one side is already double. It will cast to double automatically. -
here's very easy way and work well.. urValue.Tostring("F2")
let say.. int/double/decimal urValue = 100; urValue.Tostring("F2"); result will be "100.00"
so F2 is how many decimal place u want if you want 4 place, then use F4
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